3 red 6 blue Bag B: 4 red and 8 blue, Bag A: 2 red 6 blue Bag A: 2 red 4 blue and Bag B: 3 red 6 blue is a correct solution. Bag A: 1 red and 3 blue May I recommend that it be added to this problem that students provide the probability for drawing red from each bag? Some students will say that the probability is 1/2 for both bags instead of 1/3. Bag A has 1 red and two blue. Probability Line. 5 red and 10 green. Bag A: 3 red and 6 blue and Bag B can equal 2 red and 4 green. All rights reserved. Example: Marbles in a Bag. Required fields are marked *. bag B has 9 red and 27 green, 2 red marbles and 3 blue marbles in bag a and 6 red marbles and 9 blue marbles in bag b, one possible answer is bag a: 2 red and 6 blue; bag b: 5 red and 1 green, bag a: 3 red and 6 blue and bag B equal 2 red and 4 green. This is from a timed competition, fastest answers are best. To find probability of two results in a row, multiply chance of first result by chance of second result. Bag A: 1 red and 3 blue Bag B: 2 red and 6 blue. The question is: Suppose you have three bags containing only red marbles and blue marbles. Number of ways it can happen: 4 (there are 4 blues) Total number of outcomes: 5 (there are 5 marbles in total) So the probability = 4 5 = 0.8. Bag B has 2 red and 6 green, bag A has 1 red and 3 blue One answer is bag A is 3 red and 6 blue and bag B is 4 red and 8 green. Bag A: 3 red and 6 blue Bag B: 4 red and 8 blue. Tags 7.SP.8c DOK 2: Skill / Concept Erick Lee, Directions: The perimeter of a triangle is 20 units. Consider the solution provided by Cristian Alvaredo. Open Middle is the registered trademark of the Open Middle Partnership. of ways. Let's pretend I have a bag of 40 marbles. The red is 1/2 & 1/2 chance in both bags. Bag B : 2 Red and 4 Blue, Bag A: 3 red and 6 Blue There are _____ red marbles and _____ green marbles in Bag B. 1 red 2 blue Bag B: 2 red and 4 blue, One answer is Bag 1. B bag : 1 red, 1 Bleu. there is a 2/5 chance for each bag, Your email address will not be published. © 2016-2020 Open Middle Partnership. Bag B : 2 red and 4 green, Bag A : 3 Red and 6 Blue Now 2 marbles out of 10 can be selected total in C(10, 2) = 10!/2!×8! How can you have a different number of red marbles but the same likelihood of selecting a red marble and both bags? So the next time: if we got a red marble before, then the chance of a blue marble next is 2 in 4. if we got a blue marble before, then the chance of a blue marble next is 1 in 4 Probability does … Bag one has two red marbles and four blue marbles, bag two has eight red marbles and four blue marbles, and bag three has one red marble and three blue marbles. But without asking for the probability of drawing a red, we might not catch the misconception. Step 2: Look for all the available paths (or branches) of a particular outcome. Bag B : 4 red and 8 green. If the probability of both marbles being red is half the probability of both marbles being green, then what is the minimum possible number of marbles in the bag? Bag A has 1 red and 3 blue bag B has 3 red and 9 green, bag A has 3 red and 9 blue Bag A: 2 red 4 blue and Bag B: 3 red 6 blue is a correct solution. Bag A = 2 red, 3 blue 5 red and 10 green, One answer is Bag 1. Bag A: 3 red and 6 blue Bag A: 2 red and 4 blue; Bag B: 3 red and 6 green. Directions: There are _____ red marbles and _____ blue marbles in Bag A. Arithmetic w/ Polynomials & Rational Expressions, Reasoning with Equations and Inequalities, Linear, Quadratic, and Exponential Models, Similarity, Right Triangles, and Trigonometry, Expressing Geometric Properties with Equations, Interpreting Categorical and Quantitative Data, Making Inferences and Justifying Conclusions, Conditional Probability & the Rules of Probability, Comparing Hundredths and Tenths 2 Open Middle, Comparing Hundredths and Tenths 1 Open Middle, Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License. Bag A: 3 red and 6 blue; Bag B: 2 red and 4 green, One possible answer is bag a would equal 2 red And 4 blue, bag b would equal 3 red and 6 green. What is the probability that a blue marble gets picked? There are total ( 2+3+5) = 10 marbles in the bag and out of these 10 marbles 3 are red . What are the chances of getting a blue marble? 19 marbles are red, 21 marbles are blue. Bag 2. = 45 no. We can show probability on a Probability Line: Probability is always between 0 and 1. Example: there are 5 marbles in a bag: 4 are blue, and 1 is red. But after taking one out the chances change! The chance is 2 in 5. You can do 1 red and 2 blue for bag A, and 3 red and 6 green for bad B. Probability is Just a Guide. Step 3: Multiply along the branches and add vertically to find the probability of the outcome. 2 blue and 3 red marbles are in a bag. Bag 2. Using whole numbers, how many sets …, Bag A: 1 red and 2 blue; Bag B: 3 red and 6 green, Another possible correct answer is: Another way is to have 1 red and 2 blue for bag A, and 6 red and 12 green for bad B. I am having an issue with a conditional probability question. Save my name, email, and website in this browser for the next time I comment. Bag B: 2 red and 6 blue. Using the digits 1 to 9 at most one time each, fill in the boxes to make the probability of drawing a red marble from either bag the same. 2 red and 4 blue for Bag 1 as for Bag 2 there is 3 red and 6 blue. I tried setting up a system of equations $2(\frac{2}{x}\cdot\frac{1}{x-1})=\frac{x-2}{x} \cdot\frac{x-3}{x-1}$ This method is neither correct or … There are at least two marbles of each color in the bag. Bag A: 2 red and 4 blue; Bag B: 3 red and 6 green, Bag A: 1 red and 4 blue; Bag B: 2 red and 8 green, Bag a: 3 red and 6 blue, Bag b: 4 red and 8 green, Bag A : 3 red and 6 blue But without asking for the probability of drawing a red, we might not catch the misconception. Bag B: 4 red 12 green, Bag Ahas 2 red and 4 blue while Bag B has 3 red and 6 green, Bag A has 2 red and 4 blue while Bag B has 3 red and 6 green, BagA:1 red and 2 blue BagB:3 red and 6 green, A bag : 1 Red , 1 Bleu 2 red and 4 green, One answer is Bag 1. Your email address will not be published. Step 1: Draw the Probability Tree Diagram and write the probability of each branch. Probability Examples A jar contains 30 red marbles, 12 yellow marbles, 8 green marbles and 5 blue marbles What is the probability that you draw and replace marbles 3 times and you get NO red marbles? Some students will say that the probability is 1/2 for both bags instead of 1/3. The reason I suggest that is because I have noticed a misconception students have when solving this.